56b^2-17b=3

Solution for 56b^2-17b=3 equation:

Simplifying
56b2 + -17b = 3

Reorder the terms:
-17b + 56b2 = 3

Solving
-17b + 56b2 = 3

Solving for variable 'b'.

Reorder the terms:
-3 + -17b + 56b2 = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + -17b + 56b2 = 0

Factor a trinomial.
(-1 + -8b)(3 + -7b) = 0

Subproblem 1
Set the factor '(-1 + -8b)' equal to zero and attempt to solve:

Simplifying
-1 + -8b = 0

Solving
-1 + -8b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -8b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -8b = 0 + 1
-8b = 0 + 1

Combine like terms: 0 + 1 = 1
-8b = 1

Divide each side by '-8'.
b = -0.125

Simplifying
b = -0.125
Subproblem 2
Set the factor '(3 + -7b)' equal to zero and attempt to solve:

Simplifying
3 + -7b = 0

Solving
3 + -7b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -7b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -7b = 0 + -3
-7b = 0 + -3

Combine like terms: 0 + -3 = -3
-7b = -3

Divide each side by '-7'.
b = 0.4285714286

Simplifying
b = 0.4285714286
Solution
b = {-0.125, 0.4285714286}